Check out Aptitude Percentage Practice Questions with Answers for Banks, SSC, Railway and All other competitive exams.All Multiple Choice Questions (MCQ’s) are picked from previous year papers and various text books.
Q1. The cost of a meal in a restaurant is ₹500. A service charge of 10% is added, and then 18% GST is applied on the total amount after the service charge. What is the final amount to be paid?
Correct Answer:
₹637
Explanation: Total after Service Charge = $\text{Cost of Meal} \times \left( 1 + \frac{10}{100} \right)$
$\text{Total after Service Charge} = 500 \times 1.1 = 550$Add GST:
$\text{Final Amount} = \text{Total after Service Charge} \times \left( 1 + \frac{18}{100} \right)$
$\text{Final Amount} = 550 \times 1.18 = 649$
The final amount to be paid is ₹649.
Q2. Two numbers are in the ratio 3:5. If 20% of the smaller number is added to 30% of the larger number, the result is 62. Find the two numbers.
Correct Answer:
15 and 25
Explanation: Let the two numbers be $3x$ and $5x$:
Smaller number = $3x$, Larger number = $5x$.Given that 20% of the smaller number and 30% of the larger number sum up to 62:
$20% \times (3x) + 30% \times (5x) = 62$Rewrite percentages as fractions:
$\frac{20}{100} \times (3x) + \frac{30}{100} \times (5x) = 62$
$\frac{20}{100} \times (3x) + \frac{30}{100} \times (5x) = 62$Simplify the equation:
Convert to a common denominator:
$\frac{6x}{10} + \frac{15x}{10} = 62$
$\frac{21x}{10} = 62$Solve for $x$:
$x = \frac{62 \times 10}{21} = \frac{620}{21} \approx 29.52$
Q3. A shopkeeper sells an item at 20% profit. If the cost price of the item is ₹5,000, and he offers a discount of 10% on the selling price, what is the final selling price?
Q4. The population of a city is 2,00,000. It increases by 5% in the first year and then decreases by 10% in the second year. What is the population at the end of two years?
Correct Answer:
1,89,000
Explanation: Calculate the population after the first year:
$\text{Population after Year 1} = \text{Current Population} \times \left( 1 + \frac{\text{Increase Percentage}}{100} \right)$
$\text{Population after Year 1} = 2,00,000 \times \left( 1 + \frac{5}{100} \right)$
$= 2,00,000 \times 1.05 = 2,10,000$ Calculate the population after the second year:
$\text{Population after Year 2} = \text{Population after Year 1} \times \left( 1 - \frac{\text{Decrease Percentage}}{100} \right)$
$\text{Population after Year 2} = 2,10,000 \times \left( 1 - \frac{10}{100} \right)$
$= 2,10,000 \times 0.90 = 1,89,000$
Q5. A shopkeeper buys an article for ₹1,500 and marks it at ₹2,000. He gives a discount of 10% on the marked price and then charges 18% GST on the discounted price. What is the final price paid by the customer?
Correct Answer:
₹1,980
Explanation: Calculate the discount amount:
Discount = Marked Price X Discount Percentage. Discount = ₹2,000 X $\frac{10}{100}$ = ₹200
Calculate the price after discount:
Price after Discount = Marked Price- Discount
Price after Discount = ₹2,000 - ₹200 = ₹1,800
Calculate GST amount:
GST =Price after Discount X GST Percentage.
GST = ₹1,800 X $\frac{18}{100}$ = ₹324
Calculate the final price:
Final Price = Price after Discount + GST
Final Price = ₹1,800 + ₹324 = ₹1,962
Q6. A company\'s revenue increased from ₹2,50,000 to ₹3,00,000 in one year. What is the percentage increase in the company\\\'s revenue?
Q7. Sunita bought a mobile phone for ₹15,000. The value of the phone depreciates by 20% every year. What will be the value of the phone after two years?
Correct Answer:
₹7,200
Explanation:
Value after 1 year= Original Value X (1 - Depreciation Rate)
$ = 15,000 \times (1 - 0.2) = 15,000 \times 0.8 = 12,000 $ Value after 2 years = Value after 1 year X (1 - Depreciation Rate)
$ \text{Value after 2 years} = 12,000 \times 0.8 = 9,600 \times 0.8 = 7,200 $
Q8. A bag is marked at ₹1,200. If the seller offers a 15% discount, and GST at 18% is added after the discount, what is the final price of the bag?
Q11. The ratio of boys to girls in a school is 5:3. If 40% of the boys and 25% of the girls participate in a sports event, what percentage of the total students participate in the event? Assume there are 400 boys in the school.
Correct Answer:
32.5%
Explanation: Let the number of boys be $5x$ and the number of girls be $3x$. Given that $5x = 400$:
$x = \frac{400}{5} = 80$
Number of girls:
$3x = 3 \times 80 = 240$ Number of boys participating:
$40% \times 400 = \frac{40}{100} \times 400 = 160$ Number of girls participating:
$25% \times 240 = \frac{25}{100} \times 240 = 60$ Total participants:
$160 + 60 = 220$ Total students:
$400 + 240 = 640$ Percentage:
$\text{Percentage} = \frac{\text{Participants}}{\text{Total Students}} \times 100 = \frac{220}{640} \times 100 = 34.375%$
Q12. A shopkeeper buys 100 units of an item at ₹50 each. He marks them at ₹80 each but offers a 25% discount. Calculate his overall percentage profit.
Correct Answer:
40% profit
Explanation: Cost price for 100 units = 100 × ₹50 = ₹5,000. Marked price per unit = ₹80. Discount = 25%. Selling Price per Unit=Marked Price X $ \left(1 - \frac{25}{100}\right) $ = ₹80×0.75=₹60 Selling price for 100 units = 100 x ₹60 = ₹6,000.
Profit = Selling Price - Cost Price = ₹6,000 - ₹5,000 = ₹1,000. Percentage Profit = $ \frac{₹1,000}{₹5,000}\times{100} = 20% $
Q13. A person earns ₹80,000 monthly. He spends 40% on household expenses, 20% on rent, and 10% on miscellaneous expenses. He invests the remaining amount in a fixed deposit earning 12% annual interest. How much interest does he earn in a year from his fixed deposit?
Correct Answer:
₹58,600
Explanation: Total expenditure = 40% + 20% + 10% = 70%.
Savings percentage = 100% - 70% = 30%.
Monthly savings = 30% of ₹80,000 = $ \frac{30}{100}\times80,000 $ = 24,000. Annual savings = ₹24,000 × 12 = ₹2,88,000. Annual interest = Principal Amount X $ \frac{Rate}{100}\times{Time}\left({Years}\right) $. P = ₹2,88,000, R = 12%, T = 1 year. Interest = ₹2,88,000 x $\frac{12}{100}$x1 = ₹57,600
Q14. A man invests ₹10,000 in a scheme offering 12% annual interest compounded quarterly. How much will he have at the end of 2 years?
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